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Displacement operator : ウィキペディア英語版
Displacement operator

The displacement operator for one mode in quantum optics is the shift operator
:\hat(\alpha)=\exp \left ( \alpha \hat^\dagger - \alpha^\ast \hat \right ) ,
where \alpha is the amount of displacement in optical phase space, \alpha^
* is the complex conjugate of that displacement, and \hat and \hat^\dagger are the lowering and raising operators, respectively.
The name of this operator is derived from its ability to displace a localized state in phase space by a magnitude \alpha. It may also act on the vacuum state by displacing it into a coherent state. Specifically,
\hat(\alpha)|0\rangle=|\alpha\rangle where |\alpha\rangle is a coherent state, which is the eigenstates of the annihilation (lowering) operator.
== Properties ==
The displacement operator is a unitary operator, and therefore obeys
\hat(\alpha)\hat^\dagger(\alpha)=\hat^\dagger(\alpha)\hat(\alpha)=\hat,
where \hat is the identity operator. Since \hat^\dagger(\alpha)=\hat(-\alpha), the hermitian conjugate of the displacement operator can also be interpreted as a displacement of opposite magnitude (-\alpha). The effect of applying this operator in a similarity transformation of the ladder operators results in their displacement.
:\hat^\dagger(\alpha) \hat \hat(\alpha)=\hat+\alpha
:\hat(\alpha) \hat \hat^\dagger(\alpha)=\hat-\alpha
The product of two displacement operators is another displacement operator, apart from a phase factor, has the total displacement as the sum of the two individual displacements. This can be seen by utilizing the Baker-Campbell-Hausdorff formula.
: e^ - \alpha^
*\hat} e^ - \beta^
*\hat} = e^ - (\beta^
*+\alpha^
*)\hat} e^.
which shows us that:
:\hat(\alpha)\hat(\beta)= e^ \hat(\alpha + \beta)
When acting on an eigenket, the phase factor e^ appears in each term of the resulting state, which makes it physically irrelevant.〔Christopher Gerry and Peter Knight: ''Introductory Quantum Optics''. Cambridge (England): Cambridge UP, 2005.〕

抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)
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